Significant Conversion Factors – Chemistry Exam
The key terms of Chemistry Exam include, Significant, Figures, Conversion, Factors.
How many grams of chloride are present in 8.45 g of calcium chloride?
Atomic masses:
Ca = 40.08
Cl = 35.5
Group of answer choices
5.40g
8.45g
2.70g – correct
4.23g
How many kilograms are present in 6.78×1025molecules of Al2(SO4)3? (hint 1kg=103g)
Atomic masses:
Al = 27
S = 32
O = 16
Group of answer choices
0.891kg
Cannot be determined – correct
8.44kg
38.5kg
Classify the element Ar
nonmetal – correct
No answer text provided.
metalloid
metal
Which subatomic particles have a negative charge?
neutrons
protons
electrons – correct
No answer text provided.
How many molecules of C4H10 are present in 5.6 grams of C4H10 ? Hint 2 conversion factors are needed. Avogadro’s number and molecular weight.
Atomic weights to use:
C = 12
H = 1
Group of answer choices
5.6 molecules C4H10
5.8×1022molecules C4H10 – correct
None are correct
2.6×1023molecules C4H10
What is the proportionality between CHCl3 and Cl respectively?
3CHCl3:3Cl
1CHCl3:1Cl
1CHCl3:3Cl – correct
3CHCl3:1Cl
What conversion factor would be used to solve the following problem:
Convert 8.99g of CO2 to moles of CO2
Group of answer choices
Avogadro’s number
Molecular weight – correct
Grams
How many grams of chloride are present in 8.45 g of calcium chloride?
Atomic masses:
Ca = 40.08
Cl = 35.5
Group of answer choices
5.40g
8.45g
2.70g – correct
4.23g
How many kilograms are present in 6.78×1025molecules of Al2(SO4)3? (hint 1kg=103g)
Atomic masses:
Al = 27
S = 32
O = 16
Group of answer choices
0.891kg
Cannot be determined – correct
8.44kg
38.5kg