Significant Conversion Factors – Chemistry Exam

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Significant Conversion Factors – Chemistry Exam

The key terms of Chemistry Exam include, Significant, Figures, Conversion, Factors.



How many grams of chloride are present in 8.45 g of calcium chloride?

Atomic masses:

Ca = 40.08

Cl = 35.5

Group of answer choices

5.40g

8.45g

2.70g – correct

4.23g


How many kilograms are present in 6.78×1025molecules of Al2(SO4)3? (hint 1kg=103g)

Atomic masses:

Al = 27

S = 32

O = 16

Group of answer choices

0.891kg

Cannot be determined – correct

8.44kg

38.5kg


Classify the element Ar

nonmetal – correct

No answer text provided.

metalloid

metal


Which subatomic particles have a negative charge?

neutrons

protons

electrons – correct

No answer text provided.


How many molecules of C4H10 are present in 5.6 grams of C4H10 ? Hint 2 conversion factors are needed. Avogadro’s number and molecular weight. 

Atomic weights to use:

C = 12

H = 1 

Group of answer choices

5.6 molecules C4H10

5.8×1022molecules C4H10 – correct

None are correct

2.6×1023molecules C4H10


What is the proportionality between CHCl3 and Cl respectively?

3CHCl3:3Cl

1CHCl3:1Cl

1CHCl3:3Cl – correct

3CHCl3:1Cl


What conversion factor would be used to solve the following problem:

Convert 8.99g of CO2 to moles of CO2

Group of answer choices

Avogadro’s number

Molecular weight – correct

Grams

Density


How many grams of chloride are present in 8.45 g of calcium chloride?

Atomic masses:

Ca = 40.08

Cl = 35.5

Group of answer choices

5.40g

8.45g

2.70g – correct

4.23g


How many kilograms are present in 6.78×1025molecules of Al2(SO4)3? (hint 1kg=103g)

Atomic masses:

Al = 27

S = 32

O = 16

Group of answer choices

0.891kg

Cannot be determined – correct

8.44kg

38.5kg



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