Chemical Reaction & Enzymes – Biology Exam
The key terms of Biology Exam include, Chemical Reaction, Enzymes, Substrate.
For all the experiments carried out in Chapters 6 & 7 (Enzymes 1 & 2), the main difference between the Experimental and Control runs is that Control runs lacked __________.
| a. water |
| b. citrate buffer |
| c. substrate |
| d. enzyme – correct |
What type of inhibitor was used for our experiments in Chapter 7 (Enzymes 2)?
| a. Non-competitive Inhibitor |
| b. Competitive Inhibitor – correct |
Enzymes are NECESSARY for reactions to happen. Without them, reactions will NOT occur.
| True |
| False – correct |
Identify the SUBSTRATE being used in today’s experiments.
| a. Acid Phosphatase |
| b. Citrate Buffer, pH 5 containing 3.3mM KH2PO4 |
| c. P-Nitrophenol |
| d. P-Nitrophenyl Phosphate – correct |
Imagine you have the following data on the conversion of Magical Colorless Substance A, which undergoes a chemical reaction to be converted to Yellow KoolAid.
Amt of Yellow KoolAid (umol): 0, 0.05, 0.1, 0.2
Absorbance at 405nm: 0, 0.15, 0.3, 0.7
Draw Standard Curve where x-axis is umol of Yellow KoolAid and y-axis is Absorbance at 405nm. Then answer the following questions.
What is the umol amt of Yellow KoolAid produced for the following Absorbance at 405nm value: 0.5?
| a. 0.235 | |
| b. 0.15 umol – correct | |
| c. 0.06 umol |
Imagine you have the following data on the conversion of Magical Colorless Substance A, which undergoes a chemical reaction to be converted to Yellow KoolAid.
Amt of Yellow KoolAid (umol): 0, 0.05, 0.1, 0.2
Absorbance at 405nm: 0, 0.15, 0.3, 0.7
Draw Standard Curve where x-axis is umol of Yellow KoolAid and y-axis is Absorbance at 405nm. Then answer the following questions.
What is the umol amount of Yellow KoolAid produced for the following Absorbance at 405nm value: 0.8?
| a. 0.3 umol |
| b. 0.15 umol |
| c. 0.235 umol – correct |
A catalyst or enzyme is a substance that increases the ___________ of a chemical reaction without being consumed or permanently altered in the process.
| rate – correct |
| speed |
How long is the incubation period for each of the 4 experiments carried out in Chapter 7?
| a. 20 minutes |
| b. 10 minutes |
| c. 25 minutes |
| d. 15 minutes – correct |
our “Standard Curve exercise”, a stock solution with a known product concentration was used to create a series of tubes with lesser concentrations in a process known as “serial dilution”.
| True – correct |
| False |
The main goals of the Enzymes 1 and 2 labs were to make and use a Standard curve and enable students to see the importance of enzymes in chemical reactions, as well as the effect of temperature, pH, and the addition of substrate concentration with or without inhibitors.
| True – correct | |
| False |
For all the experiments carried out in Chapters 6 & 7 (Enzymes 1 & 2), the main difference between the Experimental and Control runs is that Control runs lacked __________.
| a. water |
| b. citrate buffer |
| c. substrate |
| d. enzyme – correct |
What type of inhibitor was used for our experiments in Chapter 7 (Enzymes 2)?
| a. Non-competitive Inhibitor |
| b. Competitive Inhibitor – correct |
Enzymes are NECESSARY for reactions to happen. Without them, reactions will NOT occur.
| True |
| False – correct |
Identify the SUBSTRATE being used in today’s experiments.
| a. Acid Phosphatase |
| b. Citrate Buffer, pH 5 containing 3.3mM KH2PO4 |
| c. P-Nitrophenol |
| d. P-Nitrophenyl Phosphate – correct |