Balanced Equations - Stoichiometry Worksheet - Chemistry

Stoichiometry Worksheet, Balanced Equations, Grams, Reactant, Limiting Reactant

The key terms in this Chemistry course include Stoichiometry Worksheet, Balanced Equations, Grams, Reactant, Limiting Reactant, Excess Reactant, Product, Reaction, Theoretical yield, Calculations, P4, Cl2, PCl₃, H3PO4, Fe2O3,H2O, CO, Fe, CO2, P4O10, Stoichiometry Worksheet – Chemistry.

Using the three balanced equations below, do 9.a through 9.d for each:
1. How many grams of the first product can be produced from 20.0 grams of the first reactant and 20.0 grams of the second reactant?
2. Which reactant is the limiting reactant?
3. How many grams of the excess reactant are reacted?
4. How many grams of the excess reactant are left unreacted?

P4 + 6Cl2 ➡ 4PCl3 P4O10 + 6H2O ➡ 4H3PO4 Fe2O3 + 3CO ➡ 2Fe+ 3CO2

9 a.	9 a.	9 a.
9 b. 9 c.	9 b. 9 c.	9 b. 9 c.
9 d.	9 d.	9 d.

P4 + 6Cl2 ➡ 4PCl3

How many grams of the first product can be produced from 20.0 grams of the first reactant and 20.0 grams of the second reactant?

68.71 g 2^nd reactant needed.

A student carried out the reaction shown by reacting 10.0g P₄with excess Cl₂and obtained 35.0g of PCl₃.

P₄+ 6Cl₂ ➡ 4PCl₃

What is the theoretical yield of PCl₃?

Calculate the % yield ofPCl₃

Calculations

10. A student carried out the reaction shown by reacting 10.0g P₄with excess Cl₂and obtained 35.0g of PCl₃.

P₄ + 6Cl₂ ➡ 4PCl₃

Theoretical Yield of PCl₃

10 x (1/123.9) x (4/1) x (137.88/1) = 44.51g

% Yield of PCl₃

(35/44.51) x 100 = 78.63 %

Using the three balanced equations below, do 9.a through 9.d for each:
1. How many grams of the first product can be produced from 20.0 grams of the first reactant and 20.0 grams of the second reactant?
2. Which reactant is the limiting reactant?
3. How many grams of the excess reactant are reacted?
4. How many grams of the excess reactant are left unreacted?

P4 + 6Cl2 ➡ 4PCl3P4O10 + 6H2O ➡4H3PO4Fe2O3 + 3CO ➡ 2Fe+ 3CO2

9 a.	9 a.	9 a.
9 b. 9 c.	9 b. 9 c.	9 b. 9 c.
9 d.	9 d.	9 d.